Reflection in Video

This is second reflection for the class of Mathematics education 2008. There are some videos containing different means. We watch video together only from Mr. Marsigit’s laptop. It’s cause by the lacking of facilities in our university. So, we get any difficulties to understand the stories in video.

But, I will try to retell the video in my posting.

The first video is “Dead Poets Society”. That video tells about William Shakphere. From that video we can study about views. If we view thing we must not only from one view, but also in much views. We must try to find our choice and improve that choice.

Second video, there is a boy speech in front of adults. He advice the adult people to still have confidence in every condition.
We must believe with our skill and we should believe “other people” to improve our skill.

The most interesting video to all is the third video. This video give different thing about mathematics to University student. There are two men sing a song. The song tell all about mathematics. There are exponent, grade, multiple, matrix, etc. This video try to show that mathematics can be made as interesting thing.

Next video contain about math truly. The title of video is “ Solve an Integral Equations” ( solving differential equations).

It is about the way to find y= f(x) if dy over dx = .4x square
• Multiple both of the segment with dx.
dy multiple by ( dy over dx ) = 4x square multiple by dx
So, we get
dx ( dy / dx ) = ( 4x ) square. dx.

• Integrate the both of segment,
integral of dy = ( 4x ) square. dx
y = (4x/3) cubed + c

• try to get variable

The next video is Solving Algebraic Equations. There are some prolem:
1. x – 5 = 3
the ways to solving are,
• add both of the segment with 5.
x – 5 + 5 = 3 + 5
x = 8
2. 7 = 4a – 1
• add both of the segment with 1 to eliminate -1.
So, 7 + 1 = 4a + 1 – 1
We find, 8 = 4a.
• multiple both of the segment with one-fourth
4a multiple by one-fourth equal 8 multiple by one-fourth
4a. (1/4) = 8( 1/4 )
a= 2

3. ( 2/3 ) x = 8
• multiple both of the segment with 3/2 to find x.
(3/2) . ( 2/3 )x = 8 . ( 3/2 )
so,
x = 12

4. 5 – 2x = 3x + 1
• add both of the segment with 2x
5 – 2x + 2x = 3x + 2x + 1
• so, 5= x + 1
• add both of the segment with -1
5 – 1 = x + 1 – 1
• we get it x = 4

5. 3 – 5(2m – 5 ) = -2
• It is equivalent with 3- 10 m + 25 = -
- 10 m = -30
• Devide both of the segment with 10.
• Multiple both of the segment with (-1)
• We get, x = 5
It is all about video 5.

Next video is Solving Logarithm Equations.
There are equation
1. log base x A equal B. it is similar with x power B equal A.
log base x A equal B equivalent with x power B equal A.
devided the left segment with C,
so C ( log base x A ) =BC,….(1)
and the right segment to be with C.
so,( X to be B) to be C = A to be C
we get, log base x A to be C = BC,…(2)
back to equation (1)
C ( log base x A) = BC equivalent with log base x A to be C = BC ,..(2)
The result,
equation (1) similar with equation (2).

2. log base x A + log base x B equal log base x (A multiple by B)
Analog, log base x A = l so, x to be l = A
log base x B= m so, x to be m = B
log base x (A multiple by B) = n,
so
x to be n = A multiple by B.
= (x to be l) multiple by (x to be n)
= x to be ( l + m)
n = l + m
so,
log base x A + log base x B equal log base x (A multiple by B)


3.log base x A - log base x B equal log base x (A devided by B)
Analog, log base x A = l so, x to be l = A
log base x B= m so, x to be m = B
log base x (A devided by B) = n, so
x to be n = A devided by B.
= (x to be l) devided by (x to be n)
= x to be ( l - m)
n = l - m
so,
log base x A - log base x B equal log base x (A devided by B)